Atrash company is designing an open-top, rectangular container that will have a volume of 3645 ft cubed. the cost of making the bottom of the container is $5 per square foot, and the cost of the sides is $4 per square foot. find the dimensions of the container that will minimize total cost.

L=9.3 ft

b=9.3 ft

h=42.14 ft

Step-by-step explanation:

Given

volume(V)=

let L,b,h be length ,breadth and height of cube

Bottom cost=5Lb

Side Costs=8Lh+8bh

Total cost(C)=5Lb+8Lh+8bh

C=

considering to be fixed ,cost become the function of L+b

and if h is fixed then Lb is also fixed and for cost to be minimum L+b should be minimum therefore L=b is necessary

thus

C=

For minimum cost differentiate w.r.t b

L=9.3 ft

h=42.14 ft

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2