What is the sum of the geometric sequence 1,3,9 if there are 10 terms

Step-by-step explanation:

We know that the terms of the sequence is 1, 3, 9

We're trying to find the total if there are 10 terms.

We know that:

We need to find the sum for 10 terms

To do this, we would use the equation:

Plug in 1 to a, 3 to r, and 10 to n

Now, you solve:

When you're done solving, you should get 29524.

you need a common difference between consecutive terms to be constant, like 1,2,3,4 or 2,4,6,8, or 1,3,6,9

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116