In a sample of 35 high school seniors, 14 of them are attending college in the fall. find the 95% confidence interval for the true proportion of high school seniors that will attend college in the fall from the population.

Between 23.77% and 56.23%

Step-by-step explanation:

On your TI-84

Press STAT

Use right arrow to scroll over to highlight TESTS

Use down arrow to scroll down to A:1-PropZInt...

Press ENTER

Make the screen read

x:14  

n:35

C-Level:0.95

Calculate

highlight  Calculate

Press ENTER

See this:

(.2377,.5623)

p(hat)=.4

n=35

The confidence interval is 0.2377 < p < 0.5623

Between 23.77% and 56.23%

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!