Farmer planting corn and soybeans: a farmer has a 320 acre farm on which she plants two crops: corn and soybeans. for each acre of corn planted, her expenses are $50 and for each acre of soybeans planted, her expenses are $100. each acre of corn requires 100 bushels of storage and yields a profit of $60; each acre of soybeans requires 40 bushels of storage and yields a profit of $90. if the total amount of storage space available is 19,200 bushels and the farmer has only $20,000 on hand, how many acres of each crop should she plant in order to maximize her profit? what will her profit be if she follows this strategy?

Let x represents acres of corn to be planted.

Let y represents acres of soybeans to be planted.

A farmer has a 320 acre farm on which she plants two crops. We get;

Other equations as per scenario becomes:

We have to find the profit. So let the profit be p. We can give this by:

When we graph these functions, we get the following.

(0,200) putting these in we get profit as $1800

(140,130) , we get $20,100

(192,0) we get $11520

In the graph, we have points (240,180) but this is not possible as so, we have (140,130) to get the maximum profit.

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation:

i believe your answer is 99.7% of 7-year-old children are between 46.6 inches and 49.5 inches tall.