Factor the expression below x^2+16x+64 a) (x-4)(x-16) b) (x-8) (x-8) c) (x+8) (x+8) d) (x+4) (x+16)

You must remember that a polynomial is written like so...

ax^2 + bx + c

In this case...

a = 1

b = 16

c = 64

To factor you must find two numbers who both add up to b (16) AND multiply to c (64)

8 + 8 = 16

8 * 8 = 64

so...

C) (x + 8)(x + 8)

Hope this helped!

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