the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters. if a component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02 centimeters is about % and the probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is about %.

1) 68.3%

2)33.3%

Step-by-step explanation:

Given:

mean, x= 5 cm

Standard deviation, sd= 0.02 cm

probability that the length of this component is between 4.98 centimeters and 5.02 centimeters=?

probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is =?

As the graph shows the normal distribution

a component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02 centimeters is about:

1 sd on either side of the mean on normal distributed graph means

P(|z|<1)

=2(0.3418)

=0.683

=68.3%

the probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is about:

=P(1<z<2) (since between 1 and 2 std dev from the mean)

between 1 and 2 sd on either side of the mean on normal distributed graph means

P(1<z<2)

=0.47-0.342

=0.333

=33.3%!

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

you can't solve x because it is 2 linear equation and you only have one equation