What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?

and

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

Now we need to find when f'(x)=0 to find the critical values.

The critical values will be

for any integer n

between 0 and 2 pi, the critical values will be

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

We need to see if the second derivative is positive or negative to determine if it is a max or min.

Since the second derivative is negative at

and

we know both of those are the x-values of maximums.

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

192/15 = 12.8.

12.8

step-by-step explanation:

192/15 is 12.8.

however, it says to round to the nearest foot, which would equal 13.