Which of the following is cot(theta) sec(theta) in simplified form? csc theta tan theta –1 1

csc(theta)

Step-by-step explanation:

we have

cot(theta)*sec(theta)

we know that

cot(theta)=cos(theta)/sin(theta)

sec(theta)=1/cos(theta)

csc(theta)=1/sin(theta)

so

substitute in the given expression

cot(theta)*sec(theta)=(cos(theta)/sin(theta))*(1/cos(theta))

Simplify

(cos(theta)/sin(theta))*(1/cos(theta))=1/sin(theta)

and

1/sin(theta)=csc(theta)

therefore

cot(theta)*sec(theta)=csc(theta)

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.