Find the required annual interest rate to the nearest tenth of a percent for $1,400 to grow to $1,800 if interest is compounded quarterly for 9 yr.

Step-by-step explanation:

For this problem, you should use the equation . For this problem, A=1800, P=1400, n=4, r=x, t=9.

A = Final Amount

P = Principal (Original Amount)

n = Number of times it is compounded in a year. (Quarterly = 4)

r = Interest Rate (In the equation, you must convert your final answer to percent form)

t = Amount of years

the interest rate  required is  r = 2.8 % compounded quarterly.

Step-by-step explanation:

principle (P) = $1,400

Grow to (A)  = $1,800

compounded quarterly hence time = 9 year

                                                           = 9 × 4 = 36

rate will be equal to r/4

now,

r = 2.8 %

hence, the interest rate  required is  r = 2.8 % compounded quarterly.

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.