Aball is dropped to the ground from a height of 100 meters. it rebounds to a height of 50 meters after that first bounce and 25 meters after the second bounce. how high will it rebound on the seventh bounce?

0.78125 m

Step-by-step explanation:

First term of this geometric series is 50 m, and the common ratio is 1/2.

Thus, a(n) = (50 m)(1/2)^(n-1)

After the 7th bounce, the ball will reach a height of a(7) = (50 m)(1/2)^(7 - 1), or

a(7) = 50 / (2^6) m = 0.78125 m

yes

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116