![\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/0156/7084/07cd5.png)
![\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill](/tpl/images/0156/7084/ca596.png)
Me! i really need y'
an object is launched from a platform.
its height (in meters), x...
Mathematics, 01.08.2019 03:10 arod20061
Me! i really need y'
an object is launched from a platform.
its height (in meters), x seconds after the launch, is modeled by:
h(x)= -5(x-4)^2+180
what is the height of the object at the time of launch?
meters
Answers: 1
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