The probability that mary will win a game is 0.02, so the probability that she will not win is 0.98. if mary wins, she will be given $160; if she loses, she must pay $16. if x = amount of money mary wins (or loses), what is the expected value of x? (round your answer to the nearest cent.)

Given:

Probability of winning, P(X) = 0.02

Probability of losing, P() = 0.98

Wining amount = $160

Losing amount = $16

Step-by-step explanation:

Let the expected amount of money win be  'X'

Expected value of X, E(X) = Probability of winning, P(X).Probability of winning, P(X)  - Probability of losing, P().Losing amount

Now,

E(X) = ()

E(X) = -12.48

Expected value of X = -12.48

Expected loss value = $12.48 loss

2x^2+5x+17

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