Astudent is taking two courses, history and math. the probability the student will pass the history course is 0.60, and the probability of passing the math course is 0.70. the probability of passing both is 0.50. what is the probability of passing at least one

The probability that students will passing at least on course=0.80.

Step-by-step explanation:

We are given that  a student is taking two courses, history and math.

The probability the student will pass the history course =P(A)=0.60

The probability that the student will pass the math course=P(B)=0.70

The probability that the students will pass the both course=

We have to find the probability that student passing at least one course.It means we have to find the probability of

We know that formula

Using the formula we get

The probability that students will passing at least on course=0.80.

i think it would be 42cm

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk