What are the real numbers for x^2-3x+8=0

Has no real solution (only imaginary solutions)

Step-by-step explanation:

x²-3x+8=0

recall for a quadratic equation in the form

ax² + bx + c = 0

the if b²- 4ac is negative (i.e less than zero), then the equation has no real solutions.

in this case,

a=1, b = -3 and c=8

b²- 4ac,

= (-3)² - (4)(1)(8)

= 9 - 32

= - 23 (negative number hence no real solutions)

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

x = 12

y = 15

step-by-step explanation: