Solve the homogeneous linear odes with constant coefficients: y" - 6y' + 8y = 0. m^2 - 6m + 8 = 0 (m - 2)(m - 4) m_1 = 2 m_2 = 4 y = c_1 e^2x + c_2 x e^4x y" - 6y' + 9y = 0. m^2 - 6m + 9 = 0 (m - 3)^2 = 0 m_1 = m_2 = 3 y = c_1 e^3x + c_2 x e^3x y" - 6y' 10y = 0. y"' + 3y" + 3y' + y = 0 y_1 = x^4 is a solution to the ode x^2 y" - 7xy' + 16y = 0, use reduction of order to find another independent solution.

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

ƒ = 0.03b

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step-by-step explanation:

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.