subject
Mathematics, 30.07.2019 21:30 lLavenderl

Solve the homogeneous linear odes with constant coefficients: y" - 6y' + 8y = 0. m^2 - 6m + 8 = 0 (m - 2)(m - 4) m_1 = 2 m_2 = 4 y = c_1 e^2x + c_2 x e^4x y" - 6y' + 9y = 0. m^2 - 6m + 9 = 0 (m - 3)^2 = 0 m_1 = m_2 = 3 y = c_1 e^3x + c_2 x e^3x y" - 6y' 10y = 0. y"' + 3y" + 3y' + y = 0 y_1 = x^4 is a solution to the ode x^2 y" - 7xy' + 16y = 0, use reduction of order to find another independent solution.

ansver
Answers: 1

Another question on Mathematics

question
Mathematics, 21.06.2019 20:30
What’s 8y+48 and factor each expression completely
Answers: 2
question
Mathematics, 21.06.2019 22:40
Aclassmate thinks that solving a system by graphing gives an exact answer when the lines appear to cross at a grid point, but only an approximate answer when they don't. explain why this isn't true.
Answers: 3
question
Mathematics, 22.06.2019 02:00
The statement tan theta= -12/5, csc theta=-13/12, and the terminal point determained by theta is in quadrant two
Answers: 3
question
Mathematics, 22.06.2019 02:00
Zack and tia played chess for 50 min they put the chessboard away at 11: 20 when did they start
Answers: 1
You know the right answer?
Solve the homogeneous linear odes with constant coefficients: y" - 6y' + 8y = 0. m^2 - 6m + 8 = 0 (...
Questions
question
Mathematics, 29.10.2020 20:40
question
Mathematics, 29.10.2020 20:40
question
Mathematics, 29.10.2020 20:40
Questions on the website: 13722366