Solve the ivp dy/dt = 2t/(y + t^2 y), y(0) = -2.

Step-by-step explanation:

Given that

This is a differential equation.

Now by separating variables

Now by integrating both side

Now by soling above integration

We know that  integration of dx/x is lnx.

Where C is the constant.

Given that when t=0 then y= -2

So by putting the above values of t and y we will find C

4=2 ln(1)+C     (we know that ln(1)=0)

So C=4

⇒

So solution of above equation is  

step-by-step explanation: