and the matrix 
for each variable. The matrix 
![\therefore A=\left[\begin{array}{cc}2&5\\1&4\end{array}\right]](/tpl/images/0151/5961/987cf.png)
, replace in the matrix A the 1st column with the results of the equations:![B_1=\left[\begin{array}{cc}1&5\\2&4\end{array}\right]](/tpl/images/0151/5961/7a671.png)
, replace in the matrix A the 2nd column with the results of the equations:![B_2=\left[\begin{array}{cc}2&1\\1&2\end{array}\right]](/tpl/images/0151/5961/98695.png)
:
:
is formed by replacing the 3rd column of A with the results of the equations:
![\therefore A=\left[\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right]](/tpl/images/0151/5961/93e8c.png)
![B_1=\left[\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right]](/tpl/images/0151/5961/0a91f.png)
![B_2=\left[\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right]](/tpl/images/0151/5961/97fe6.png)
![B_3=\left[\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right]](/tpl/images/0151/5961/8292e.png)
(a) 2x1 + 5x2 =1 x1+4x2=2
Mathematics, 30.07.2019 19:20 delanorpalmer24
Solve these linear equations by cramer's rules xj=det bj / det a:
(a) 2x1 + 5x2 =1 x1+4x2=2
(b) 2x1+x2=1 x1+2x2+x3=0 x2+2x3=0
Answers: 3
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You know the right answer?
Solve these linear equations by cramer's rules xj=det bj / det a:
(a) 2x1 + 5x2 =1 x1+4x2=2
(a) 2x1 + 5x2 =1 x1+4x2=2
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