Aball is launched into the air from below a cliff, such that after t seconds its height above the cliff top is hmetres, and is given by the equation
h =  − 4.9t^2 + 19.6t − 12.6.
calculate, to the nearest metre, the maximum height the ball achieves above the cliff top.

7 meters

Step-by-step explanation:

In order to find the answer we need to calculate the first derivative of the function as follows:

Now, for obtaining the time 't' when the ball reaches the maximum height:

Finally, we use the original equation for determining the height after 2 seconds:

In conclusion, the maximum height above the cliff top is 7 meters.

it is 10.6 according to my calculations

you estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82 .the total height of the building is another 123 meters above the 86th floor.

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