Pl ! hurry
i'll reward u with everything
show that

Step-by-step explanation:

note :

tanx = sinx/cosx      and secx = 1/cosx

1+tan²(2π/3) =  1+(sin2π/3/cos2π/3)²

= 1 +( sin2π/3)²/(cos2π/3)²

=( sin2π/3)²+(cos2π/3)²/(cos2π/3)²

but :   ( sin2π/3)²+(cos2π/3)²=1

so :1+tan²(2π/3) = 1 /(cos2π/3)²

                          =( 1/cos2π/3)²

:1+tan²(2π/3) =sec²( 2π/3)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )