What polynomial has roots of −6, −4, and 1?
x3 − 9x2 − 22x + 24
x3 − x2 − 26x − 24
x3 + x2 − 26x + 24
x3 + 9x2 + 14x − 24

x^3+9x^2+14x-24 has roots of -6,-4 and 1

Option D is correct

Step-by-step explanation:

If the polynomial has roots of -6 -4 and 1

then x=-6, x=-4, x=1

Which can be written as:

(x+6)(x+4)(x-1)

Multiplying we get,

(x+6)(x(x-1)+4(x-1))

(x+6)(x^2-x+4x-4)

(x+6)(x^2+3x-4)

x(x^2+3x-4)+6(x^2+3x-4)

x^3+3x^2-4x+6x^2+18x-24

x^3+3x^2+6x^2-4x+18x-24

x^3+9x^2+14x-24

So, x^3+9x^2+14x-24 has roots of -6,-4 and 1

Option D is correct

sorry not sure

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.