One zero of the polynomial function f(x) = x3 + x2 + 20x is x = 0. what are the zeros of the polynomial function?
0, −5, −4
0, −5, 4
0, 5, −4
0, 5, 4

The correct option is C

Step-by-step explanation:

if f(x)= x3 + x2 - 20x

Replace f(x) by y

y = x3 + x2 - 20x

0 =x3 + x2 - 20x

x3 + x2 - 20x = 0

Take out x as a common:

x(x2+x-20)=0

Find factors of x2+x+20.

x(x^2+4x-5x-20) = 0

x{x(x+4)-5(x+4)}=0

x(x+4)(x-5)=0

Set x= 0

x=0 , x+4=0 , x-5 =0

x=0, x=0-4 , x=0+5

x=0, x= -4, x=5

x=(0,5,-4)

The correct option is C

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."