Two forces of 7 newtons and 11 newtons act on a body at an angle of 60° to each other. find the magnitude of the resultant force to the nearest whole number.

16 N

Step-by-step explanation:

If the 7 N force is at 0°, and the 11 N force is at 60°, then the components of the resultant force are:

Fₓ = 7 cos 0° + 11 cos 60° = 12.5

Fᵧ = 7 sin 0° + 11 sin 60° ≈ 9.53

The magnitude of the resultant force is:

F = √(Fₓ² + Fᵧ²)

F ≈ 15.7

Rounded to the nearest whole number, the magnitude is 16 N.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°