Circumference, radius, slant height, lateral area, and surface area are measurements of a cone. given two of the measurements, find the other three to the nearest tenth. r = 3 ft, s. a. = 50 ft.^2 also: c = 44 in, l. a. = 176 in.^2

Step-by-step explanation:

Applicable relations are ...

  C = 2πr . . . . . . . r = radius, C = circumference

  LA = 1/2·Ch . . . . h = slant height, LA = lateral area

  SA = πr² +LA . . . SA = total surface area

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1. Given r and SA, we can find the other measures as ...

  LA = SA -πr² = 50 ft² -π(3 ft)² ≈ 21.7 ft²

  C = 2πr = 2π(3 ft) ≈ 18.8 ft

  h = 2·LA/C ≈ 2·21.7 ft²/(18.8 ft) ≈ 2.3 ft

(Please note that for calculations using intermediate results, we used the full-precision values of those results, not the rounded ones. Rounding is always the last operation. Please note, too, that we have used a value for π sufficient to ensure accuracy in all the digits shown here.)

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2. Given C and LA, we can find the other measures as ...

  h = 2·LA/C = 2(176 in²)/(44 in) = 8 in

  r = C/(2π) = (44 in)/(2π) ≈ 7.0 in

  SA = LA +πr² = LA +rC/2 ≈ 176 in² +(7.0 in)(44 in)/2 ≈ 330.1 in²

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)