Given triangle abc, which equation could be used to find the measure of ∠c? right triangle abc with ab measuring 6, ac measuring 3, and bc measuring 3 square root of 5 cos m∠c = 2 square root of 5 all over 5 sin m∠c = square root of 5 over 5 cos m∠c = square root of 5 over 2 sin m∠c = 2 square root of 5 all over 5

What about to find angle B?

Step-by-step explanation:

sin m∠C = 2 square root of 5 all over 5

Step-by-step explanation:

we know that

In the right triangle ABC

The function cosine of angle C is equal to divide the adjacent side to angle C by the hypotenuse

substitute

The function sine of angle C is equal to divide the opposite side to angle C by the hypotenuse

substitute

so

2 square root of 5 all over 5

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign