What do i do to solve this problem?

D

Step-by-step explanation:

Consider one of the circles

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

Since ΔHPU is equilateral then ∠HPU = 60°, thus

A = πr² ×

   = π × 3² ×

   = 9π × = π

Shaded area = area of circle - area of sector = 9π - π = π

Since both circles are congruent then

total shaded area = 2 × π = 15π → D

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.