What is the decibel level of the sound of a monster truck with intensity 10−2 watts per square inch? use a logarithmic model to solve.

BdB = 68.10 decibels

Step-by-step explanation:

BdB = 10 log10 I / Io

where BdB is the sound intensity level in decibels, I is the sound intensity on the linear scale (W / m²) and I0 is the hearing threshold (10^-12 W / m²).

Converting Io de 10^-12 W/m² to W/in², tenemos

10^-12 W/m² = 1.5500031000062x10^-9 W/in²

So, applying the equation or formula,

BdB = 10 log10 (10 ^ -2 W/in² / 1.5500031000062x10^-9 W/in² )

BdB = 10 log10 (0.64516x10^6)

BdB = 10 log10 (6,451,600)

Being log10 (6,451,600) = 6.8096674332398761189214526331036, then

BdB = 10 x 6.8096674332398761189214526331036

BdB = 68.096674332398761189214526331036

BdB = 68.10 decibels

12.5 feet

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4