Answers: 3
,
,
)
![I=-\frac{e^{-3t} sint}{3} - [\frac{e^{-3t} cost }{9}-\int -\frac{e^{-3t} sint}{9}dt]+C](/tpl/images/0137/7752/da6eb.png)
![I=-\frac{e^{-3t} sint}{3} - [\frac{e^{-3t} cost }{9}+\frac{1}{9}\int e^{-3t} sint dt]+C](/tpl/images/0137/7752/7f88f.png)
![I=-\frac{e^{-3t} sint}{3} - [\frac{e^{-3t} cost }{9}+\frac{1}{9} I]+C](/tpl/images/0137/7752/cca06.png)
( from equation (2))
( where, C' = 9C/10 )
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