10. suppose that we draw cards repeatedly and with replacement from a file of 100 cards, 50 of which refer to male and 50 to female persons. what is the probability of obtaining the second "female" card before the third "male" card?

11/16

Step-by-step explanation:

there are 100 cards out of which there are 50 male and 50 female cards

M= male card F= female cards

P(M)= 50/100= 1/2

P(F)= 50/100= 1/2

Following are the combination in which we can obtain second Female card before Third Male card

FF, FMF, MFF,  MMFF, MFMF, FMMF

So, P(FF)= = 1/4

P(FMF)=  = 1/8

and P(MFF)= = 1/8

P(MMFF)=

=1/16

P(MFMF)=

=1/16

P(FMMF)=

=1/16

so the required probability is the sum of all these

=1/4 + 1/8 + 1/8 + 1/16 + 1/16 + 1/16= 11/16

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

but which class are u may know that first