A32 lb weight stretches a spring 2 ft in equilibrium. it is attached to a mass with a constant c 8 lb-sec/ft. the weight is initially displaced 8 inches below equilibrium and released from rest. find its displacement for t > 0.

the answer is c just got it on ed

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

step-by-step explanation:

im not sure what the answer is

5.7622

step-by-step explanation:

the ten thousandths place is the 2. you round it up if, that number in whatever place is 5 or higher.