Aparticle moves with velocity vector
v(t) = ti - 2j + t^2 k
at time t = 0 the particle is at the point (0, −1, 1). what is the position of the particle at time t?

Step-by-step explanation:

We are given that velocity vector of a particle

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle  at time t.

We know that

Velocity =

Therefore,

Integrate on both sides then we get

Substitute the value of point at time t=0 then we get

C=

Substitute the value of C then we get

Therefore, the position of particle at time t

the answer is c)8

step-by-step explanaction:

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