You have 9 chairs arranged in a circle, and wish to seat 9 people (one person per seat). the one constraint is that person a cannot sit next to person b or person c (three of the people). how many ways are there to seat them?

30240 number of ways are there to seat them

Step-by-step explanation:

Total number of ways of arranging 9 people on 9 chairs  in circular manners = (9-1)! = 8! =

number of ways A sit always sit next to B = AB together makes a single and

                                                                       therefore total number of arrangements for this  = 7+(AB) = 8  that is 8  persons sitting in circular manner

number of ways = (8-1)! =7! = 5040

likewise number of arrangements for A and C will be = 5040

Total number of ways such that A cannot sit next to B or C = total ways of 9 persons - total number of A always sitting next to B - total number of ways always sitting next to C  = 8! - 7!-7!

                                        = 40320- 5040-5040

                                        = 30240

=  

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

2/3

step-by-step explanation: