Arectangle has a length 10 m less than twice its width. when 2 m are added to the width, the resulting figure is a square with an area of 196 m squared. find the dimensions of the original rectangle.

The length of the original rectangle is 14 meters and the width of the original rectangle is 12 meters

Step-by-step explanation:

Let

l ----> the length of the original rectangle

w ----> the width of the original rectangle

we know that

----> equation A

----> area of a square

Solve for w

square root both sides

-----> this solution not make sense

so

Find the value of L

therefore

The length of the original rectangle is 14 meters and the width is 12 meters

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.