4. below is a list of 30 students numbered from 00 to 29. use the random number table below to put exactly 6 of these students into a treatment group. start with the first line of the table (line 101). list the students of the treatment group in the order in which their numbers come up in the table.
00 aaron
01 buffy
02 chandler
03 cindy
04 drusilla
05 eric 06 fallon
07 graham
08 heather
09 hsin-chi
10 ismail
11 jasmine 12 kiefer
13 lucia
14 monte
15 naomi
16 otis
17 polly 18 quincy
19 rachael
20 sarah
21 stacy
22 tasha
23 turan 24 ukiah
25 valerie
26 wahib
27 xandra
28 yale
29 zach
part a: search through the list for pairs that match student numbers and circle each one found. if a student number is repeated, only use the first occurrence. stop when you have 6 matches. (3 points)
part b: list the 6 matching student numbers you found. (3 points)
part c: which 6 students will be in the treatment group? (3 points)

i can

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

konichiwa~! my name is zalgo and i am here to answer your anime-related question today. more than likely, kirishima would kill izuku, marry mino and kiss momo. all of this would be my opinion by the way. (and i am also a weeb lol)

i hope this you! : d

stay and stay proud! " - zalgo

(and do you think you can mark me as brainliest? i'd greatly appreciate it! arigato~! )