For the multi‑step reaction a+b⟶c+d the rate‑limiting step is unimolecular, with a as the sole reactant. if [a] and [b] are both 0.110 m, then the rate of reaction is 0.0090 m/s. what is the rate of the reaction if [a] is doubled?

Rate of reaction when concentration of A is doubled=0.018 M/s.

Step-by-step explanation:

We are given that for the multi-step reaction

It is given that the rate-limiting step is unimolecular  with A as the sole reactant

It means rate of reaction depend upon the concentration of reactant A only

Rate of reaction =k[A]

[A]=0.110 M

[B]=0.110 M

Rate of reaction =0.0090 M/s

According to rate law

Rate of reaction=k[A]

If concentration of A is doubled then the rate of reaction is given by

Rate of reaction =k[2A]= 2 k[A]=2 initial  rate of reaction

Therefore, rate of reaction after substituting values

Rate of reaction ==0.018 M/s

Rate of reaction when concentration of A is doubled=0.018 M/s.

answer: on kudzu, being female and being green are independent events.

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x