If elf is congruent to gjh, ef=12 and lf=7.8 find ij. round answer to the hundredths place. a. 4.78 b 5.62 c 4.98 d 5.07

EF = 12

KF = 6

LF = 7.8

LK = sqrt(7.8^2-6^2) = 4.98

IJ = LK

Answer with explanation:

→ΔELF ≅ Δ GHJ[Given]

→EF=GH[CPCT]

→GJ=FL[CPCT]

Let , O be the center of the circle.

→ EK=KF[Perpendicular from the center to the chord bisects the chord.]

→GI=IH[Reason same as Above]

→→EK=GI, KF=HI

→→OJ=OL

→OK=KI

→OJ-OK=OL-KI

→LK=IJ

⇒→Δ LKF ≅ Δ JIG[SAS]

Now, In Δ LKF, By Pythagorean Theorem

 →(LF)²=(LK)²+(KF)²

→(7.8)²=(LK)²+(6)²

→60.84-36=(LK)²

→24.84=(LK)²

LK=4.98

→→LK=IJ=4.98

Option C:→4.98

i am unable to solve this problem

step-by-step explanation: