Aboat leaves a dock at 9: 00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15km/h and reaches the same dock at 10: 00 pm. how many minutes after 9: 00 pm were the two boats closest together? (round your answer to the nearest minute.)

22 min

Step-by-step explanation:

we need to find the closest distance between two ship.

let us take the ships meet after time t

now distance travel by first ship at any time t is given by 20t

the position of second ship is 15-15t

let us take distance between them is d

therefore

now to get the shortest distance differentiate D w.r.t time

t=0.36hr

thus at

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

graph #4 (last graph) depict the function   f(x)= -m(x-d)^1/5 i

step-by-step explanation:

we know that

m=slope

but in this function slope is -m that means slope is decreasing and it is decreasing by 1/5 points down the x-axis.

which is shown in graph four

a decreasing slope down x-axis by 1/5 points.

hence 4th graph is the right option for this.