![\left[\begin{array}{cc}2&-2\\-1&3\end{array}\right] \cdot \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}-18\\13\end{array}\right]](/tpl/images/0123/0528/46c31.png)
![\left[\begin{array}{cc}2&-2\\-1&3\end{array}\right]](/tpl/images/0123/0528/294d4.png)
![\left|\left[\begin{array}{cc}2&-2\\-1&3\end{array}\right]\right|=2\cdot 3-(-1)\cdot (-2)=6-2=4](/tpl/images/0123/0528/b08f3.png)
![\dfrac{1}{4}\left[\begin{array}{cc}3&1\\2&2\end{array}\right]^T=\dfrac{1}{4}\left[\begin{array}{cc}3&2\\1&2\end{array}\right]](/tpl/images/0123/0528/beb3f.png)
![\left[\begin{array}{c}x\\y\end{array}\right]=\dfrac{1}{4}\left[\begin{array}{cc}3&2\\1&2\end{array}\right]\cdot \left[\begin{array}{c}-18\\13\end{array}\right]=\\ \\=\dfrac{1}{4}\left[\begin{array}{cc}3\cdot(-18)+2\cdot 13\\1\cdot (-18)+2\cdot 13\end{array}\right]=\dfrac{1}{4}\left[\begin{array}{c}-28\\8\end{array}\right]=\left[\begin{array}{c}-7\\2\end{array}\right]](/tpl/images/0123/0528/7f1ba.png)
Solve the matrix equation by using inverse matrices.
[2 -2] * [x] = [-18]
[-1 3] * [y] =...
Mathematics, 23.07.2019 10:10 maggiemae4993
Solve the matrix equation by using inverse matrices.
[2 -2] * [x] = [-18]
[-1 3] * [y] = [13 ]
Answers: 3
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