Circle x with a radius of 6 units and circle y with a radius of 2 units are shown. 

which steps would prove the circles similar?
translate the circles so they share a common center point, and dilate circle y by a scale factor of 4.
translate the circles so the center of one circle rests on the edge of the other circle, and dilate circle y by a scale factor of 4.
translate the circles so they share a common center point, and dilate circle y by a scale factor of 3. 
translate the circles so the center of one circle rests on the edge of the other circle, and dilate circle y by a scale factor of 3.
mark this and returnsave and exit  next   

Translate the circles so they share a common center point, and dilate circle Y by a scale factor of 3 ⇒ 3rd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- To prove that all circles are similar, a translation and a scale factor

  from a dilation will be found to map one circle onto another

- So we can translate the circles to share the same center and dilated

 one of them by the scale factor of the dilation and the center of

 dilation is the common center of the circles

* Lets solve the problem

∵ Circle X has a radius 6 units

∵ Circle Y has a radius 2 units

- At first we translate the circles to share the same center

∴ Use translation to put the centers of the circles at the same point

- Find the scale factor of the dilation from the radii of the two circles

∵ The radius of circle X is 6 units

∵ The radius of circle Y is 2 units

∴ The scale factor = 6/2 = 3

∴ Dilate circle y by scale factor 3

* The steps would prove the circles are similar are;

  Translate the circles so they share a common center point, and

  dilate circle Y by a scale factor of 3.

for the points

step-by-step explanation:

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.