Consider a bridge hand (that is, draw 13 cards at random and without replacement from a regular, 52-card deck). find the following probabilities: are. exactly 6 spades, 4 hearts, 2 diamonds, and 1 club

The probability of selecting exactly 6 spades, 4 hearts, 2 diamonds, and 1 club is .

Step-by-step explanation:

Total number of cards in a regular deck of cards = 52

Total number of cards of each suit (spades, hearts, diamonds, club) = 13

Total ways of selecting r cards from total n cards is

Total ways of selecting 13 cards from total 52 cards is

Total ways of selecting exactly 6 spades, 4 hearts, 2 diamonds, and 1 club is

The probability of selecting exactly 6 spades, 4 hearts, 2 diamonds, and 1 club is

Therefore the probability of selecting exactly 6 spades, 4 hearts, 2 diamonds, and 1 club is .

The probability of getting exactly 6 spades,4 hearts,2 diamond and one club=

Step-by-step explanation:

We are given that a bridge hand that draw 13 cards at random and without replacement from a regular 52 cards deck.

We have to find the probabilities

1.exactly 6 spades

We know that in one deck

Total number of spades=13

Total number of heart =13

Total number of diamond in a deck=13

Total number of clubs in a deck =13

Total number of cards=52

The probability of getting exactly 6 spades,4 hearts,2 diamond and one club=

Probability,P(E)=

The probability of getting exactly 6 spades,4 hearts,2 diamond and one club=

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step-by-step explanation:

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