If z is a standard normal variable, find the probability.
the probability that z lies between –1.10 and –0.36
0.4951
–0.2237
0.2237
0.2239

0.2237

Step-by-step explanation:

Use the Table of Standard Normal Probabilities for Negative z-scores.

For z= -0.36 NORMSDIST(-0.36)=0.3594 (read value from the table)

For z= -1.10  NORMSDIST(-1.10)=0.1357 (value from the table)

You know P(-1.10<z<-0.36) = 0.3594-0.1357=0.2237

2nd one in the first row is correct