Chris will rent a car for the weekend. he can choose one of two plans. the first plan has an initial fee of $65 and costs an additional $0.80 per mile driven. the second plan has no initial fee but costs $0.90per mile driven. how many miles would chris need to drive for the two plans to cost the same?

Chris would need to drive 650 miles for the two plans to cost the same.

Further Explanation:

Let d = distance traveled in miles

Plan 1 will have an initial fee of $65 and a cost of $0.80 per mile driven. Therefore, the total cost to drive a distance of d will be:

total cost = $65 + ($ 0.80 × d)

Plan 2 will have no initial fee but has a cost of $0.90 per mile drive. The total cost, then, to drive a distance of d will be:

total cost = $0.90 × d

If the two costs are the same, then:

$65 + ($ 0.80 × d) = $0.90 × d

The distance driven, d, can then be solved algebraically.

Combining like terms:

$65 = $0.90d - $0.80d

$65 = $0.10d

Solving for d:

d = $65/$0.10

d = 650 miles

To check the answer, solve for the total cost of Plan 1 and Plan 2 and see if they are equal.

Plan 1:

total cost = $65 + ($0.80 x 650)

total cost = $65 + $520

total cost = $585

Plan 2:

total cost = $0.90 x 650

total cost = $585

Since both plans cost the same, then the distance 650 mi is correct.

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Keywords: word problem, total cost

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