When four basketball players are about to have a free-throw competition, they often draw names out of a hat to randomly select the order in which they shoot. what is the probability that they shoot free throws in alphabetical order? assume each player has a different name.

Step-by-step explanation:

Let the names of 4 players start with letters A, B, C and D.

There is the the only chance that they shoot free throws in alphabetical order (ABCD).

Count how many different ways are to choose 4 letters from the hat. First letter can be chosen in 4 ways, the second letter can be chosen in 3 ways (only 3 letters left), the third letter can be chosen in 2 ways (only 2 letters left) and the fourth letter can be chosen in 1 way (the last letter left). So, there are

different orders.

The probability is

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )