Ajet plane travels 2 times the speed of a commercial airplane. the distance between vancouver
and regina is 1730 km. if the flight from vancouver to regina on a commercial airplane takes
140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route? ( show steps: ))

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x > the speed of a commercial airplane

y > the speed of a jet plane

t > the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x > equation A

The speed of a commercial airplane is equal to

x=1,730/(t+140) > equation B

The speed of a jet airplane is equal to

y=1,730/t > equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

The time of a commercial airplane is

t+140=140+140=280 minutes

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.