Subtract (3x2 + 2x - 9) - (6x2 - 16). write your answer as a polynomial

The answer is -3x^2+2x+7

Step-by-step explanation:

(3x2 + 2x - 9) - (6x2 - 16)

Open the parenthesis

Keep in mind that when you will open the parenthesis the signs of 2nd bracket will be multiplied by negative sign

3x^2+2x-9-6x^2+16

Arrange the terms:

3x^2-6x^2+2x+16-9

Solve the like terms:

= -3x^2+2x+7

Thus the answer is -3x^2+2x+7

= (3x²+2x-9) - (6x²-16)

= 3x² + 2x - 9 - 6x² +16

= -3x² +2x + 7

While opening the brackets, make sure you change the signs accordingly. If there is a "-" sign outside the bracket then while opening the brackets, terms inside change their signs, which means "+" becomes "-" and vice versa.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

a) 7x=7

step-by-step explanation: