In the figure, a square is inside another bigger square.
if a = 4 units and b = 3 units, the length of the diagonal of the outside square rounded to the nearest tenth is
units and the length of the diagonal of the inside square rounded to the nearest tenth is units.

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

substitute

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: