Simplify 6 plus the square root of negative 80.
6 plus 16 times the square root of 5 i
6 plus 4 i times the square root of 5
6 plus 16 i times the square root of 5
6 plus 4 times the square root of 5 i

6 plus 4 i times the square root of 5

Step-by-step explanation:

The given statement can be written as:

6+√-80

To solve √-80 re-write -80 as -1 * 80

Now √-80 =√-1 * 80

Now we can write it as:

6+ √-1 * √80

We know that √-1 = i

Thus it becomes:

6+ i√80

Now find the square root of 80

80 does not have a perfect square root

Its square root can be found as 80 = 4*4*5

Then,

6+i√4*4*5

Notice that 4 makes a pair.. So we will write it outside the square root

6+1*4√5

We will write it as:

6+4i√5

Thus the correct option is 6 plus 4 i times the square root of 5

answer: idk

step-by-step explanation:

can i see the following ?

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