To predict the number of species (n) that live in a region of some area (a), biologists use the logarithmic model n = k log a, where k is some constant. if 5,800 species live in a rain forest that has an area of 750 square kilometers (km2), approximately how many species will be left after half of the rain forest is destroyed due to an amusement park being built there? hint: first you need to solve for the constant k.

There are 5193 species will be left

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of species (n) that live in a region of some area (A), can

  be found by using the logarithmic model n = k log A where k is

  a constant

- If 5,800 species live in a rain forest that has an area of 750 square

 kilometers

∴ n = 5800 species

∴ A = 750 km²

- Substitute the value of A and n in the equation to fined k

∵ A = 750 , n = 5800

∵ n = k log A

∴ 5800 = k log (750)

- Divide both sides by log (750)

∴ k = 5800 ÷ log (750)

∴ k = 2017.34

- Lets substitute the value of k in the equation

∴ n = 2017.34 log A

- The half of the rain forest is destroyed due to an amusement park

  being built there

∴ The new area is 1/2 the old area

∵ The old area is 750

∴ The new area = 1/2 × 750 = 375 km²

- Lets substitute this value in the equation to find the number of

 species will be left in the new area

∵ A = 375

∴ n = 2017.34 log (375) = 5192.696 ≅ 5193

∴ There are 5193 species will be left

robert puts 2 in each row

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.