If x and p are both greater than zero and 4x^2p^2+xp-33=0, then what is the value of p in terms of x?
a) -3/x
b) -11/4x
c) 3/4x
d) 11/4x

Explanation:

1) Make a change of variable:

2) The new equation with u is:

3) Factor the left side of the new equation:

4) Come back to the equation replacing the left side with its factored form and solve:

5) Come back to the original substitution:

If u = - 3 ⇒ xp = - 3 ⇒ x or p is negative and that is against the condition that x and p are both greater than zero, so this solution is discarded.

Then use the second solution:

Solve for p:

1,8,15,22,29,36,43,50

step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)