Three consecutive multiples of 7 have a sum of 84. what is the greatest these numbering?
a. 7
b. 21
c. 35
d. 42

  C.  35

Step-by-step explanation:

Let x represent the largest of the multiples of 7. The sum will be ...

  x + (x -7) + (x -14) = 84

  3x = 105 . . . . . . . . . . . . . add 21 and simplify

  x = 35 . . . . . . . . . . . . . . . divide by 3

The greatest of the numbers of interest is 35.

Two consecutive multiples of 7 will differ by 7. If x is the largest, the next-largest is x-7, and the one before that is x-14.

hi,

3. 12.15, you are correct.

4.2.01, your first digit is correct,

hope this !

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: