Which formulas can be used to find the surface area of a regular pyramid with a square base where the perimeter of the base is equal to p, s is the slant height, ba is the base area, and la is the lateral area? check all that apply. a. sa = ba - la b. sa = ba + ps c. sa = ba + ps d. sa = ba la e. sa = ba + la

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

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555.99.

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make sure you have version 2.50

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